Two forces act on this node. Add a third that brings it into equilibrium — adjust F3's x and y components until both sums hit zero.
coordinate convention: right = +x, up = +y
A free body diagram isolates a structure and shows every force acting on it — the first step in any structural analysis.
Every structural calculation begins with a free body diagram. Isolate the body you want to analyze — cut it free from its surroundings. Replace every connection, support, and contact with the forces and moments they exert. Draw all applied loads. Now you have a complete picture of every force acting on that body. Without an FBD, you're guessing. With one, equilibrium gives you the answer.
Three rules for a correct FBD: (1) Include ALL forces — applied loads, self-weight, reactions at supports, internal forces at cuts. Missing one makes the whole analysis wrong. (2) Show the correct number of reactions per support type — pin gives 2 (Rx, Ry), roller gives 1 (Ry), fixed gives 3 (Rx, Ry, M). (3) Assume directions for unknowns and let the math tell you if you're right — a negative answer just means the force acts opposite to your assumed direction.
An engineer's first move is always the same: isolate the thing you're analyzing. Cut it free from everything around it. Replace every connection, every support, every contact point with an arrow representing the force at that location. What you're left with is a free body diagram — the object, floating alone, with every force that acts on it shown explicitly.
This sounds abstract. It isn't. If you're standing still, gravity pulls you down. The floor pushes you up. Those two forces are equal and opposite. You are in equilibrium. A node in a structure is the same idea — except instead of two forces, there might be three or four, and they might not be vertical. The FBD makes sure you account for all of them.
For a 2D problem with no rotation, equilibrium means two things are simultaneously true:
That's the whole framework. Every force has an x-component and a y-component. You add them up separately. If both totals are zero, nothing is moving, nothing is accelerating. The system is in static equilibrium.
In the sandbox above, F1 pulls down (-8 in y) and F2 pushes right (+5 in x). For the node to stay still, something has to push up with +8 and pull left with -5. That's what you just found.
When a structural engineer analyzes a building, they assume it is not moving. Not accelerating. Not about to tip over or slide sideways. That assumption — static equilibrium — is what makes the math solvable.
Every beam, every column, every connection in a structure is assumed to satisfy SFx = 0 and SFy = 0 (and SM = 0, which you'll meet in the statics module). If any of those equations aren't satisfied, the structure is either moving or failing.
This is why FBDs matter. You can't check equilibrium on something you haven't isolated. You can't find the forces if you haven't drawn them. The diagram isn't busywork — it's the only way to make sure you haven't missed anything.
Use the sandbox above to find the equilibrium force, then enter your values in the "check your work" section to verify. If you found F3x = -5 kips and F3y = +8 kips, the node is in equilibrium.